Question

Acetamide on reduction using Na/C₂H₅OH gives ____________.

Options

• CH₃NH₂

• (CH₃)₃N

• CH₃CH₂NH₂

• (C₂H₅)₂NH

Answer 1

Acetamide on reduction using Na/C₂H₅OH gives CH₃CH₂NH₂.

Explanation:

\[\begin{array}{cc}
\ce{O}\phantom{.....................................}\\
||\phantom{.....................................}\\
\ce{\underset{\text{Acetarnide}}{CH3 -C -  NH2} + 4[H] ->[Na/C2H5OH] \underset{\text{Ethylamine}}{CH3 - CH2 - NH2}}
\end{array}\]