Question

\[\ce{Acetone + Methyl magnesium iodide ->[i. Dry ether][ii. HOH/H^+] P}\]

'P' in above reaction is:

Options

• 2, 2-methylpropane-2-diol

• butan-2-ol

• 2-methylpropan-2-ol

• propan-2-ol

Answer 1

2-methylpropan-2-ol

Explanation:

\[\begin{array}{cc}
\phantom{.........................}\ce{O}\phantom{..................................}\ce{CH3}\phantom{}\\
\phantom{......................}||\phantom{...................................}|\phantom{}\\
\ce{\underset{Methyl magnesium iodide}{CH3 - Mg - I} + \underset{\underset{(Acetone)}{Propanone}}{CH3 - C - CH3} ->[i. Dry ether ii. HOH/H^+][-MgI(OH)] CH3 - C - OH}\\
\phantom{..........................................................}|\\
\phantom{.............................................................}\ce{\underset{\underset{{'P'}}{2-Methylpropan-2-ol}}{CH3}}
\end{array}\]