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After 18 years, Swarnim will be 4 times as old as he is now. His present age is ______. - Mathematics

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Question

After 18 years, Swarnim will be 4 times as old as he is now. His present age is ______.

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Solution

After 18 years, Swarnim will be 4 times as old as he is now. His present age is 6 years.

Explanation:

Let Swarnim’s present age be x year.

After 18 year, Swarnim’s age = (x + 18) year

According to the question,

x + 18 = 4x

⇒ x – 4x = –18  ...[Transposing 4x to LHS and 18 to RHS]

⇒ –3x = –18

⇒ `(-3x)/(-3) = (-18)/3`  ...[Dividing both sides by –3]

∴  x = 6

Hence, Swarnim’s present age is 6 year.

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Chapter 4: Linear Equation In One Variable - Exercise [Page 113]

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NCERT Exemplar Mathematics [English] Class 8
Chapter 4 Linear Equation In One Variable
Exercise | Q 29. | Page 113
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