Question

Alternating current of peak value `(2/pi)` ampere flows through the primary coil of transformer. The coefficient of mutual inductance between primary and secondary coil is 1 H. The peak e.m.f. induced in secondary coil is ______. (Frequency of a.c. = 50 Hz)

Options

• 100 V

• 400 V

• 300 V

• 200 V

Answer 1

Alternating current of peak value `(2/pi)` ampere flows through the primary coil of transformer. The coefficient of mutual inductance between primary and secondary coil is 1 H. The peak e.m.f. induced in secondary coil is 200 V. (Frequency of a.c. = 50 Hz)

Explanation:

M = 1 H      f = 50 Hz

`"i"_"op" = 2/pi "A"       "i"_"os" = ?`

`"I"_"p" = 2/pi "sin"  omega"t"  "A"`

`abs"e"  = "M" ("dI"_"p")/"dt"`

` = "M""d"/"dt" (2/pi "sin"  omega"t")`

`= (2"M"omega)/pi  "cos"  omega "t"`

`abs"e" _"max" = (2"M"omega)/pi`

`= (2 xx 1 xx 2pi xx 50)/pi`

`= 200  "V"`