Question

An aeroplane, with its wings spread 10 m, is flying at a speed of 180 km/h in a horizontal direction. The total intensity of earth's field at that part is 2.5 × 10^-4 Wb/m² and the angle of dip is 60°. The emf induced between the tips of the plane wings will be ______.

Options

• 108.25 mV

• 88.37 mV

• 62.50  mV

• 54.125 mV

Answer 1

An aeroplane, with its wings spread 10 m, is flying at a speed of 180 km/h in a horizontal direction. The total intensity of earth's field at that part is 2.5 × 10^-4 Wb/m² and the angle of dip is 60°. The emf induced between the tips of the plane wings will be 108.25 mV.

Explanation:

Emf induced ε_ind = (B_v) LV and

B_v = `"B"_"Total"`sin 60°

= (2.5 × 10^-4) (sin 60°) × 10 × 180 × `5/18`

= `2.5xx 10^-4xxsqrt3/2xx500`

= 108.25 mV