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Question
An alternating emf is applied to a series combination of an inductor and a resistor (R = 100 Ω ). If the impedance of the circuit is `100 sqrt2 Ω`, what is the phase difference between the emf and the current?
Numerical
Solution
Data: R = 100 Ω, Z = `100 sqrt2 Ω`
cos Φ = `R/Z`
= `100/(100sqrt2)`
= `1/sqrt2`
∴ `Φ = cos^-1 (1/sqrt2)`
= π/4 rad
= 45°
This is the phase difference between the emf and the current.
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Second Law of Thermodynamics
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