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Question
An ammeter is obtained by shunting 'n' `Omega` galvanometer with 'n' `Omega` resistance. The additional shunt required to be connected across it to double the range is ____________.
Options
n
`"n"/4`
`"n"/3`
`"n"/2`
Solution
An ammeter is obtained by shunting 'n' `Omega` galvanometer with 'n' `Omega` resistance. The additional shunt required to be connected across it to double the range is `"n"/2`.
Explanation:
Initially `"S" = "i"_"g"/("I" - "i"_"g") xx "G"`
`"n" = "i"_"g"/("I" - "i"_"g") xx "n"`
`"i"_"g" = "I" - "i"_g Rightarrow "I" = 2"i"_"g"`
`"When the rang is double I'" = 2"I" = 4"i"_"g"`
`"Now, S'" = "i"_"g"/("I'" - "i"_g) "G"`
`= "i"_"g"/(4"i"_"g" - "i"_"g") xx "n"`
`= 1/3 "n"`
Since shunt is connected in parallel, so additional shunt required is
`1/"S'" = 1/"S" + 1/"X"`
`1/"X" = 1/"S'" - 1/"S"`
`3/"n" - 1/"n" = 2/"n"`
`therefore "X'" = "n"/2`