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Question
An ant moved for several seconds and covered 3 mm in the first second and 4 mm more in each successive second than in its predecessor. If the ant had covered 1 mm in the first second and 8 m more in each successive second, then the difference between the path it would cover during the same time and the actual path would be more than 6 mm but less than 30 mm. Find the time for which the ant moved (in seconds)
Options
5 s
4 s
6 s
None of these
Solution
4 s
Explanation:
Let ant move for t second
Case I :
St when ant move 3 m min first second and 4 m min in each second.
`"S"_"n"="t"/2[2(3)+("t"-1)4]`
Case II :
St when ant move 1 mm in the first second and 8 mm in each second
`"S"_"t"="t"/2[2("v")+("t"-1)8]`
ATQ,
`6<"t"/2[2+("t"-1)8]-"t"/2[6+("t"-1)4]<30`
`6<"t"/2[-8+4"t"]<30`
6 <[− 4t + 2t2]< 30
From option putting t = 4 Only condition is satisfied
6 < − 16 + 32 < 30
6 < 16 < 30