Question

An body is dropped from the top of a tower. It acquires a velocity 20 m s^-1 on reaching the ground. Calculate the height of the tower. (Take g = 10 m s^-2)

Answer 1

Initial velocity u = 0

Final velocity = 20 m/s

g = 10 m/s²

Let 'h' be the height of the tower.

Using the third equation of motion,

v² - u² = 2gs

or, (20)² - 0 = 2 (10) h

or, h = 20 m