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Tamil Nadu Board of Secondary EducationSSLC (English Medium) Class 6

An electrician buys a used T.V. for ₹ 12,000 and a used Fridge for ₹ 11,000. After spending ₹ 1000 on repairing the T.V. and ₹ 1500 on painting the Fridge, he fixes up the M.P. of T.V. - Mathematics

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Question

An electrician buys a used T.V. for ₹ 12,000 and a used Fridge for ₹ 11,000. After spending ₹ 1000 on repairing the T.V. and ₹ 1500 on painting the Fridge, he fixes up the M.P. of T.V. as ₹ 15,000 and that of Fridge as ₹ 15,500. If he gives ₹ 1000 discount on each find his profit or loss

Sum

Solution

(i) Cost of a T.V. = ₹ 12,000

Paid for repair = ₹ 1,000

C.P. of the T.V. = 12,000 + 1000 = ₹ 13,000

M.P of the T.V. = ₹ 15,000

Discount on a T.V. = ₹ 1000

S.P. = M.P. – Discount

= 15,000 – 1000

= ₹ 14,000

Here S.P. > C.P.

Profit = S.P. – C.P.

= 14,000 – 13,000

= ₹ 1,000

Profit on the T.V. = ₹ 1,000

(ii) Cost of the Fridge = ₹ 11,000

Painting charge = ₹ 1500

C.P. of the Fridge = 11000 + 1500 = ₹ 12,500

M.P of the Fridge = ₹ 15,500

Discount allowed = ₹ 1000

S.P. = M.P – Discount

= ₹ 15,500 – ₹ 1000

= ₹ 14,500

Here also S.P. > C.P.

Profit = ₹ 14,500 – ₹ 12,500

= ₹ 2000

Total profit = Profit on T.V. + Profit on Fridge

= ₹ 1000 + ₹ 2000

= ₹ 3000

Profit = ₹ 3000

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Chapter 3: Bill, Profit and Loss - Exercise 3.2 [Page 56]

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Samacheer Kalvi Mathematics - Term 2 [English] Class 6 TN Board
Chapter 3 Bill, Profit and Loss
Exercise 3.2 | Q 8 | Page 56
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