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Question
An electron in a hydrogen atom has an energy of -3.4 eV. The difference between its kinetic and potential energy is ______.
Options
10.2 eV
-10.2 eV
-13.6 eV
Both 10.2 eV and -10.2 eV
Solution
An electron in a hydrogen atom has an energy of -3.4 eV. The difference between its kinetic and potential energy is both 10.2 eV and -10.2 eV.
Explanation:
According to Bohr's model, the kinetic energy of a moving electron in the nth orbit is given as
K = `(Rhc)/n^2` ......(i)
where, R = Rydberg constant, h = Planck's constant and c = speed of light.
Similarly, the potential energy of an electron moving in the nth orbit,
P = `-2(Rhc)/n^2` .........(ii)
From Eqs. (i) and (ii), we have
P = -2K
The total energy of the electron moving in the nth orbit,
E = K + P = K - 2K
E = -K
⇒ K = -E = -(-3.4 eV) [given, E = -3.4 eV]
⇒ K = 3.4 eV
From Eq. (iii), we have
P = -2K = -2(3.4) = -6.8 eV
∵ P - K = -6.8 - 3.4 = -10.2 eV
and K - P = 3.4 - (-6.8) = 10.2 eV