English

An electron of mass 'm' is rotating in first Bohr orbit of radius 'r' in hydrogen atom. The orbital acceleration of the electron in first orbit (h = Planck's constant). -

Advertisements
Advertisements

Question

An electron of mass 'm' is rotating in first Bohr orbit of radius 'r' in hydrogen atom. The orbital acceleration of the electron in first orbit (h = Planck's constant).

Options

  • h/4 π2mr2

  • h/2 π2

  • h2/2π2 m2r2

  • h2/4π2 m2r2

MCQ

Solution

h2/4π2 m2r

Explanation:

L = mvr = `"nh"/(2pi)`

`therefore "v" = "nh"/(2pi"mr")`

`=> "v"^2 = ("n"^2"h"^2)/(4pi^2"m"^2"r"^2)`

`=> "v"^2/"r" = ("n"^2"h"^2)/(4pi^2"m"^2"r"^3)`

shaalaa.com
Bohr’s Atomic Model
  Is there an error in this question or solution?
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×