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Question
An element has a bee structure with cell edge of 288 pm. The density of element is 7.2 g cm-3. What is the atomic mass of an element?
Options
25.89
51.78
77.68
62.43
MCQ
Solution
51.78
Explanation:
Given,
Cell is bcc, so Z = 2
Edge length (a) = 288 pm
= 2.88 × 10-8 cm
Density of metal (d) = 7.2 g cm-3
NA = 6.022 × 1023
We know that, density (d) = `("Z" xx "M")/("a"^3 * "N"_"A")`
`therefore "M" = ("d" * "a"^3 * "N"_"A")/"Z"`
`= (7.2 xx (2.88 xx 10^-8) xx 6.022 xx 10^23)/2`
`= (7.2 xx 23.8878 xx 10^-24 xx 6.022 xx 10^23)/2`
= 51.78 g mol-1
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Atomic and Molecular Masses
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