Question

An element has a cubic structure with a cell edge of 288 pm. The density of the element is 7.2 g cm^–3. 208 g of the element has 24.16 × 10²³ numbers of atoms. The unit cell of this cubic structure is

Options

• primitive

• body-centred

• face-centred

• hexagonal

Answer 1

primitive

Explanation:

a = 288 pm = 288 × 10^–12 m = 2.88 × 10^–8 cm

p = `(M xx Z)/(a^3 xx N_0)`

Z = 7.2 g cm^–3 × 24.16 × 10²³ × (2.88 × 10^–8 cm)³ = 208