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Question
An ideal gas expands isothermally and reversibly from 10 m3 to 20 m3 at 300 K performing 5 .187 kJ of work on surrounding. Calculate number of moles of gas undergoing expansion. (R = 8.314 J K-1 mol-1)
Options
2
3
1.5
1
MCQ
Solution
3
Explanation:
V1 = 10 m3, V2 = 20 m3, T = 300 K
Wmax = - 5.187 kJ = - 5187 J, n = ?
Wmax = - 2.303 nRT `log_10 "V"_2/"V"_1`
∴ - 5187 = - 2.303 × n × 8.314 × 300 `log_10 20/10`
∴ n = `5187/(2.303 xx 8.314 xx 300 xx log_10 2)`
`= 5187/(2.303 xx 8.314 xx 300 xx 0.3010)`
∴ n = 3 mol
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