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Question
An ideal gas expands isothermally and reversibly from 10 m3 to 20 m3 at 300 K, performing 5.187 kJ of work on surrounding, calculate number of moles of gas used.
Options
1.5
1
3
2
MCQ
Solution
3
Explanation:
W = `- int "p"."dV"`
Substituting the ideal gas equation for pleads to,
W = `- int "nRT"/"V"."dV"`
Since the process is isothermal,
W = `- "nRT In" ("V"_2/"V"_1)`
`- 5.187 xx 1000 "J" = - "n" xx 8.314 "JK"^-1 "mol"^-1 "In" ((20 "m"^3)/(10 "m"^3))`
n = `(5.187 xx 1000)/(8.314 xx "In" 2)` mol
= `(5.187 xx 1000)/(8.314 xx 0.6931)` mol
= 3 mol
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Moles and Gases
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