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Question
An inclined plane makes an angle of 30° with the horizontal electric field E of 100 V/m. A particle of mass 1 kg and charge 0.01 C slides down from a height of 1 m. If the coefficient of friction is 0.2, the time taken for the particle to reach the bottom is ______ sec.
Options
1.00
2.00
3.00
4.00
Solution
An inclined plane makes an angle of 30° with the horizontal electric field E of 100 V/m. A particle of mass 1 kg and charge 0.01 C slides down from a height of 1 m. If the coefficient of friction is 0.2, the time taken for the particle to reach the bottom is 2.00 sec.
Explanation:
f = μN
= μ(qE sin30° + mg cos30°)
= `0.2(0.01 xx 100 xx 1/2 + 1 xx 10 xx 0.866)`
= 1.832 N
From the above figure,
`h/S = sin30^circ`
S = `h/(sin 30^circ) = 1/(1/2)`
S = 2 m
Net downward force
F = mg sin30° - qE cos30° - f
= `(1 xx 10 xx 1/2 - 0.01 xx 100 xx 0.866 - 1.832)`
= 5 - 0.866 - 1.832
= 2.302 N
a = `f/m = 2.30/1 = 2.30` m/s2
S = ut + `1/2`at2 (u = 0)
S = `1/2` at2
t = `sqrt((2S)/a) = sqrt((2 xx 2)/2.30)`
t = 1.32 sec