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Question
An iron rod is placed parallel to magnetic field of intensity 2000 A/m. The magnetic flux through the rod is 6 × 10−4 Wb and its cross-sectional area is 3cm2. The magnetic permeability of the rod in `"Wb"/("A" - "m")` is ____________.
Options
10−1
10−2
10−4
10−3
MCQ
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Solution
An iron rod is placed parallel to magnetic field of intensity 2000 A/m. The magnetic flux through the rod is 6 × 10−4 Wb and its cross-sectional area is 3cm2. The magnetic permeability of the rod in `"Wb"/("A" - "m")` is 10−3.
Explanation:
Given, magnetic field intensity,
H = 2000 Am−1,
Magnetic flux, Φ = 6 × 10−4 Wb,
Cross-sectional area, A = 3 cm2 = 3 × 10−4 m2
As, we know, Φ = BA and B = µH
µ = `"B"/"H" = Φ/("AH") = (6 xx 10^-4)/(3 xx 10^-4 xx 2000)`
= 10−3 Wb A−1 m−1
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