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Question
An open pipe of certain length produces fundamental frequency f1. A closed pipe of some other length produces fundamental .frequency f2. When the two are joined to form a longer close tube, its fundamental frequency will be ____________.
Options
`("f"_1"f"_2)/("f"_1 + "f"_2)`
`(2"f"_1"f"_2)/("f"_1 + "f"_2)`
`("f"_1"f"_2)/("f"_1 + 2"f"_2)`
`("f"_1"f"_2)/(2"f"_1 + "f"_2)`
Solution
An open pipe of certain length produces fundamental frequency f1. A closed pipe of some other length produces fundamental .frequency f2. When the two are joined to form a longer close tube, its fundamental frequency will be `("f"_1"f"_2)/("f"_1 + 2"f"_2)`.
Explanation:
`"For open pipe," "f"_1 = "v"/(2"L"_1) or "L"_1/(2"f"_1)`
`"For closed pipe,""f"_12= "v"/(4"L"_2) or "L"_2/(4"f"_2)`
After joining the two pipes we get,
L = L1 + L1
Since it is a closed pipe,
`"f" = "v"/(4"L") = "v"/(4("L"_1 + "L"_2)) = "v"/(4(v/(2"f"_1) + "v"/(4"f"_2)))`
`= (8"f"_1 "f"_2)/(4(4"f"_2 + 2"f"_1))`
` = ("f"_1 "f"_2)/(2"f"_2 +"f"_1)`