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Question
An organic compound (A) with molecular formula C2Cl3O2H is obtained when (B) reacts with Red P and Cl2. The organic compound (B) can be obtained on the reaction of methyl magnesium chloride with dry ice followed by acid hydrolysis.
- Identify A and B.
- Write down the reaction for the formation of A from B. What is this reaction called?
- Give any one method by which organic compound B can be prepared from its corresponding acid chloride.
- Which will be the more acidic compound (A) or (B)? Why?
- Write down the reaction to prepare methane from the compound (B).
Short Note
Solution
- (A): CCl3COOH (B): CH3COOH
- \[\ce{CH3COOH ->[(i) Red P/Cl2][(ii) H2O] CCl3COOH,}\]Hell Volhard Zelinsky reaction
- \[\ce{CH3COCl ->[H2O] CH3COOH}\]
- A will be more acidic due to presence of 3Cl groups (electron withdrawing groups) which increase acidity of carboxylic acid.
- \[\ce{CH3COOH ->[(i) NaOH, CaO (ii) Heat] CH4 + Na2CO3}\]
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