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Question
Answer the following in brief.
How will you determine activation energy from rate constants at two different temperatures?
Solution
Determination of activation energy from rate constants at two different temperatures.
Arrhenius equation is k = `"Ae"^((-"E"_"a")/("RT"))`
From two different temperatures T1 and T2
log10k1 = log10A - `"E"_"a"/(2.303"RT"_1)` ....(1)
log10k2 = log10A - `"E"_"a"/(2.303"RT"_2)` ....(2)
where k1 and k2 are the rate constants at temperatures T1 and T2 respectively. Subtracting Eq.(1) from Eq.(2),
log10k2 - log10k1 = `-"E"_"a"/(2.303"R") 1/"T"_2 + "E"_"a"/(2.303"R") 1/"T"_1`
Hence, `"log"_10 "k"_2/"k"_1 = "E"_"a"/(2.303"R") (1/"T"_1 - 1/"T"_2) = "E"_"a"/(2.303"R") (("T"_2 - "T"_1)/("T"_1"T"_2))`
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