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Answer the following: Show that there is no constant term in the expansion of (2x-x24)9 - Mathematics and Statistics

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Question

Answer the following:

Show that there is no constant term in the expansion of `(2x - x^2/4)^9`

Sum

Solution

Let, if possible, tr+1 is the constant term in the expansion of `(2x - x^2/4)^9`.

We know that, in the expansion of (a+ b)n,

tr+1 = nCr,  an–r br

Here a = 2x, b = `- x^2/4`, n = 9

tr+1 = `""^9"C"_"r" (2x)^(9 - "r") (-x^2/4)^"r"`

= `""^9"C"_"r" 2^(9 - "r") * x^(9 - "r")*(-1/4)^"r" x^(2"r")`

= `""^9"C"_"r"* 2^(9 - "r")* (-1/4)^"r"* x^(9 + "r")`

But tr+1 is a constant term

∴ power of x = 0

∴ 9 + r = 0

∴ r = – 9

This is not possible, because r ∈ N.

Hence, there is no constant term in the expansion of `(2x - x^2/4)^9`.

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General Term in Expansion of (a + b)n
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Chapter 4: Methods of Induction and Binomial Theorem - Miscellaneous Exercise 4.2 [Page 86]

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Balbharati Mathematics and Statistics 2 (Arts and Science) [English] 11 Standard Maharashtra State Board
Chapter 4 Methods of Induction and Binomial Theorem
Miscellaneous Exercise 4.2 | Q II. (17) | Page 86

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