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Question
Are the following pair of linear equations consistent? Justify your answer.
`3/5x - y = 1/2, 1/5x - 3y = 1/6`
Sum
Solution
Conditions for pair of linear equations to be consistent are:
`a_1/a_2 ≠ b_1/b_2` ......[Unique solution]
`a_1/a_2 = b_1/b_2 = c_1/c_2`......[Coincident or infinitely many solutions]
Yes.
The given pair of linear equations
`(3/5)x - y = 1/2`
`(1/5)x - 3y = 1/6`
Comparing the above equations with ax + by + c = 0
We get,
`a_1 = 3/5, b_1 = -1, c_1 = -1/2`
`a_2 = 1/5, b_2 = 3, c_2 = -1/6`
`a_1/a_2` = 3
`b_1/b_2 = (-1)/-3 = 1/3`
`c_1/c_2` = 3
Here, `a_1/a_2 ≠ b_1/b_2`
Hence, the given pair of linear equations has unique solution, i.e., consistent.
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