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Question
ARR[15] ft:20] is a two-dimensional array, which is stored in the memory along the row with each of its elements occupying 4 .bytes. Find the .address of the element ARR[5)[15], if the element ARR[lO] [5] is stored at the memory location 35000.
Solution
Given:
Arr[15][20]
W = 4 B = ? Lr = 0 Lc = 0 R = 15 C = 20
Address of Arr[5][15] = ?
Address of [10][5] = 35000
Address of an element (I,J) in row major = B + W(C(I - Lr) + (J - Lc))
Therefore 35000 = B + 4(20(10 - 0) + (5 - 0))
= B + 4(20 x 10 + 5)
= B + 4(200 + 5)
= B + 4 x 205
= B + 820
B = 34180
Address of Arr[5][15] = 34180 + 4(20 x 5 + 15)
= 34180 + 4(100 + 15)
= 34180 + 4 x 115
= 34180 + 460
= 34640
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