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Question
Arrange Ag, Cr and Hg metals in the increasing order of reducing power. Given:
`(E_(Ag^+)^o)/(Ag) = +0.80V`
`(E_(Cr^(+3))^o)/(Cr) = -0.74V`
`(E_(Hg^(+2))^o)/(Hg) = +0.79V`
Solution
\[\ce{->[Ag<Hg<Cr][Increasing reducing power]}\]
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