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Question
Arrange the following rational numbers in descending order.
`(-7)/(10), (-8)/(15) and (-11)/(30)`
Solution
Given numbers : `(-7)/(10), (-8)/(15) and (-11)/(30)`
The L.C.M. of 10, 15 and 30 is 30.
Thus, numbers are :
`(-7)/(10)`
= `(-7 xx 3)/(10 xx 3)`
= `(-21)/(30)`,
`(-8)/(15)`
= `(-8 xx 2)/(15 xx 2)`
= `(-6)/(30)`,
`(-11)/(30)`
Since -11 > -16 > -21, we have `(-11)/(30) > (-8)/(15) > (-7)/(10)`.
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