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Question
Assign the position of the element having an outer electronic configuration in the periodic table.
(n - 1)d2 ns2 for n = 4
Solution 1
Since n = 4, the element belongs to the 4th period. It is a d–block element as d–orbitals are incompletely filled.
There are 2 electrons in the d–orbital.
Thus, the corresponding group of the element
= Number of s–block groups + number of d–block groups
= 2 + 2
= 4
Therefore, it is a 4th period and 4th group element. Hence, the element is Titanium.
Solution 2
n = 4
Means element belongs to 4th period belongs to group 4 as in the valence shell (2 + 2) = 4 electrons.
Electronic configuration = 1s2 2s2 2p6 3s2 3p6 3d2 4s2, and the element name is Titanium (Ti).
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