Advertisements
Advertisements
Question
Assuming the expression for the pressure exerted by the gas on the wall of the container, it can be shown that pressure is ______.
Options
`[1/3]^"rd"` kinetic energy per unit volume of a gas.
`[2/3]^"rd"` kinetic energy per unit volume of a gas.
`[3/4]^"th"` kinetic energy per unit volume of a gas.
`3/2xx` kinetic energy per unit volume of a gas.
Solution
Assuming the expression for the pressure exerted by the gas on the wall of the container, it can be shown that pressure is `underlinebb([2/3]^"rd" "kinetic energy per unit volume of a gas")`.
Explanation:
Pressure exerted by the gas on wall of container is given by,
` "P" =1/3 "pv"^2` .... (v = r.m.s. speed)
` "P" =1/3 ("M"/"V")"v"^2`
` "P" = 2/3 1/2 ("M"/"V")"v"^2`
` therefore "P" = 2/3 (("K"."E")/"V")` .... `(because "K"."E" = 1/2 "Mv"^2)`
