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At 1990 K and 1 atm pressure, there are equal numbers of Cl2 molecules and Cl atoms in the reaction mixture. The value of Kp for the reaction Cl2(g) ⇌ 2Cl(g) under the above conditions is x × 10−1. -

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At 1990 K and 1 atm pressure, there are equal numbers of Cl2 molecules and Cl atoms in the reaction mixture. The value of Kp for the reaction Cl2(g) ⇌ 2Cl(g) under the above conditions is x × 10−1. The value of x is ______. (Rounded-off to the nearest integer)

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Solution

At 1990 K and 1 atm pressure, there are equal numbers of Cl2 molecules and Cl atoms in the reaction mixture. The value of Kp for the reaction Cl2(g) ⇌ 2Cl(g) under the above conditions is x × 10−1. The value of x is 5.

Explanation:

Cl2 ⇌ 2Cl

Moles of Cl2 = moles of Cl = x .....(given)

∴ Total no. of moles = x + x = 2x

\[\ce{P_{Cl_2}}\] = `"x"/(2"x") xx 1 = 1/2`

PCl = `"x"/"2x" xx 1 = 1/2`

∴ Kp = `("P"_"Cl")^2/"P"_"Cl"`

= `((1/2)^2)/(1/2)`

= `1/2`

= 0.5

= 5 × 10−1

Hence value of x = 5

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Law of Chemical Equilibrium and Equilibrium Constant
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