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Question
At a given place, a mercury barometer records a pressure of 0.70 m of Hg. What would be the height of water column if mercury in barometer is replaced by water? Take density of mercury to be = 13.6 × 103 kg m-3.
Solution
Relative Density of Hg = 1.36 = `13.6 xx 10^3 "kgm"^-3`
Acceleration due to gravity , g = 9.8 `"ms"^-2`
Height of mercury column = 0.70 m
∴ Pressure , P = hρg
or , P = `(0.7)(1.36 xx 10^3)(9.8)` pascal
or , P = `93.3 xx 10^3` Pa
Let h be the height of water column
Then , P = h (density of water) g
or , `93.3 xx 10^3 = "h" xx 10^3 xx 9.8`
or , h = 9.52 m
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