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Question
At a given temperature the pressure of a gas reduces to 75% of its initial value and the volume increases by 40% of its initial value. Find this temperature if the initial temperature was -10°C.
Solution
P1 = 1 atm.
P2 = `75/100 xx 1 = 3/4` atm.
V1 = x cc (suppose)
V2 = `140/100 "x" = 7/5 "x"`
T1 = - 10 + 273 = 263 K
T2 = ?
Using gas equation `("P"_1"V"_1)/"T"_1 = ("P"_2"V"_2)/"T"_2`
∴ T2 = `("P"_2"V"_2"T"_1)/("P"_1"V"_1)`
`= 3/4 xx "7x"/5 xx 263/(1 xx "x") = 5523/20`
T2 = `552.3/2 = 276.15`K = 276.15 - 273
∴ T2 = 3.15°C
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