Question

At constant pressure, a quantity of an ideal gas occupies 1.0 × 10⁻² dm³ volume at 200 K. At what temperature, the volume will be 2.0 × 10⁻³ dm³?

Options

• 400 K

• 40 K

• 20 K

• 250 K

Answer 1

40 K

Explanation:

`"V"_1/"V"_2 = "T"_1/"T"_2`

T₂ = `("T"_1"V"_2)/"V"_1`

= `(200  "K" xx 2.0 xx 10^-3  "dm"^3)/(1.0 xx 10^-2  "dm"^3)`

= 40 K