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At a Party, Colas, Squash and Fruit Juice Were Offered to Guests. a Fourth of the Guests Drank Colas, a Third Drank Squash, Two Fifths Drank Fruit Juice and Just Three Did Not Drink Any Thing - Mathematics

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Question

At a party, colas, squash and fruit juice were offered to guests. A fourth of the guests drank colas, a third drank squash, two fifths drank fruit juice and just three did not drink any thing. How many guests were in all?

Numerical

Solution

Let the total number of guests be x .
Therefore, the number of guests, who drank colas, would be \[\frac{1}{4}x . \]
The number of guests, who drank squash, would be \[\frac{1}{3}x . \]
The number of guests, who drank fruit juice, would be \[\frac{2}{5}x . \]
The number of guests, who did not drink, would be 3 . 
According to the question, 
\[x - (\frac{x}{4} + \frac{x}{3} + \frac{2x}{5}) = 3\]
or \[ \frac{60x - 15x - 20x - 24x}{60} = 3\]
or x = 180
Thus, total number of guests = 180.

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Chapter 9: Linear Equation in One Variable - Exercise 9.4 [Page 30]

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RD Sharma Mathematics [English] Class 8
Chapter 9 Linear Equation in One Variable
Exercise 9.4 | Q 16 | Page 30

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