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Question
At what temperature, a chemical reaction will have the following values of ∆G, ∆S and ∆H?
∆G = −5.2 KJ mol−1, ∆H = 145.6 kJ mol−1, ∆S = −216 kJ mol−1
Options
698.1 K
650.0 K
823.0 K
425.0 K
MCQ
Solution
698.1 K
Explanation:
∆G = ∆H − T∆S
−5.2 = `145.6 - "T"(-216/1000)`
−5.2 − 145.6 = `(216 "T")/1000`
T = `-(150.8 xx 1000)/216`
T = 698.1 K
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Spontaneous (Irreversible) Process
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