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Au+CNA−+HA2O+OA2⟶[Au(CN)A2]A−+OHA− The number of CN− ions involved in the balanced equation is ______. -

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Question

\[\ce{Au + CN^- + H2O + O2 -> [Au(CN)2]^- + OH^-}\]

The number of CN ions involved in the balanced equation is ______.

Options

  • 4

  • 8

  • 12

  • 16

MCQ
Fill in the Blanks

Solution

\[\ce{Au + CN^- + H2O + O2 -> [Au(CN)2]^- + OH^-}\]

The number of CN ions involved in the balanced equation is 8.

Explanation:

\[\ce{4Au + 8CN^- + 2H2O + O2 -> 4[Au(CN)2]^- + 4OH^-}\]

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