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Question
भागाकार करा. भागाकार व बाकी लिहा.
(6x5 − 4x4 + 8x3 + 2x2) ÷ 2x2
Sum
Solution
(6x5 − 4x4 + 8x3 + 2x2) ÷ 2x2
= `(6x^5 - 4x^4 + 8x^3 + 2x^2)/(2x^2)`
= `(2x^2(3x^3 - 2x^2 + 4x + 1))/(2x^2)`
= 3x3 − 2x2 + 4x + 1
∴ भागाकार = 3x3 − 2x2 + 4x + 1 व बाकी = 0
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