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Question
Bulbs are packed in cartons each containing 40 bulbs. Seven hundred cartons were examined for defective bulbs and the results are given in the following table:
Number of defective bulbs | 0 | 1 | 2 | 3 | 4 | 5 | 6 | more than 6 |
Frequency | 400 | 180 | 48 | 41 | 18 | 8 | 3 | 2 |
One carton was selected at random. What is the probability that it has defective bulbs less than 4?
Sum
Solution
Total number of cartons, n(S) = 700
Number of cartons which has defective less than 4,
n(E3) = 400 + 180 + 48 + 41 = 669
∴ The probability that the defective bulbs less than 4 = `(n(E_3))/(n(S)) = 669/700`
Hence, the probability that the defective bulbs less than 4 is `669/700.`
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