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Question
Bulbs are packed in cartons each containing 40 bulbs. Seven hundred cartons were examined for defective bulbs and the results are given in the following table:
Number of defective bulbs | 0 | 1 | 2 | 3 | 4 | 5 | 6 | more than 6 |
Frequency | 400 | 180 | 48 | 41 | 18 | 8 | 3 | 2 |
One carton was selected at random. What is the probability that it has defective bulbs from 2 to 6?
Sum
Solution
Total number of cartons, n(S) = 700
Number of cartons which has defective bulbs from 2 to 6,
n(E2) = 48 + 41 + 18 + 8 + 3 = 118
∴ Probability that the defective bulbs from 2 to 6 = `(n(E_2))/(n(S)) = 118/700 = 59/350`
Hence, the probability that the defective bulbs from 2 to 6 is `59/350.`
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