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Question
By how much is 2x − 3y + 4z greater than 2x + 5y − 6z + 2?
Solution
To calculate how much is 2x − 3y + 4z greater than 2x + 5y − 6z + 2, we have to subtract 2x + 5y − 6z + 2 from 2x − 3y + 4z.
Change the sign of each term of the expression that is to be subtracted and then add.
Term to be subtracted = 2x + 5y − 6z + 2
Changing the sign of each term of the expression gives -2x - 5y + 6z - 2.
On adding:
(2x − 3y + 4z )+(-2x - 5y + 6z - 2 )
= 2x − 3y + 4z-2x - 5y + 6z - 2
= (2-2)x + (-3-5)y +(4+6)z-2
= 0-8y+10z-2
= -8y+10z-2
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