Question

\[\ce{C6H12O6 ->[(Zymase)] A ->[NaOH][\Delta] B + CHI3}\]

The number of carbon atoms present in the product B is:

Options

• 1

• 2

• 3

• 4

Answer 1

1

Explanation:

\[\begin{array}{cc}
\phantom{..........................}\ce{O}\\
\phantom{..........................}||\\
\ce{C6H12O6 ->[Zymase] \underset{(A)}{CH3CH2OH} ->[Zymase] \underset{(B)}{H - C - \overset{-}{O}N\overset{+}{a}} + CHI3}
\end{array}\]

So, in HCOONa (B), numbers of carbon atom is 1.