Question

 Calculate the amount of heat required to change 40 G of ice at -10°C into water at 20°C. (sp. heat cap. of ice = 2.1 J/g°C, latent heat of fusion of ice = 330 j/g)

Answer 1

Amount of heat requird to convert ice from -10°C to 0°C = m x c x θ

                                                                   = 40 x 2.1 x 10 = 840 J

Amount of heat required to convert ice at 0°C to water at 0°C = mL 

                                                                                 = 40 x 330 = 13200 J

Amount of heat required to convert water at 0°C to water at 20°C

= 40 x 4.2 x 20 = 3360 J

Total heat required during the process = 17400 J