Question

Calculate ΔG for ΔH = − 110 kJ, ΔS = + 40 J K⁻¹ at 400 K.

Answer 1

Given: ΔH = − 110 kJ,

ΔS = + 40 J K⁻¹

= 40 × 10⁻³ kJ K⁻¹,

T = 400 K

ΔG = ΔH − TΔS

= − 110 kJ − (400 K × 40 × 10⁻³ kJ K⁻¹)

= − 110 kJ − 16 kJ

∴  ΔG = − 126 kJ