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Question
Calculate ΔG0 for the reaction
\[\ce{CH_{4(g)} + H_{2(g)}-> C2H_{6(g)}}\]
State whether the reaction is spontaneous or not. (Given: KP = 3.358 × 1017, T = 25° C, R = 8.314 × 10−3 kJK−1 moI−1)
Numerical
Solution
\[\ce{CH_{4(g)} + H_{2(g)}-> C2H_{6(g)}}\]
Given: KP = 3.358 × 1017, T = 25° C = 298 K
= R = 8.314 × 10−3 kJK−1 moI−1
∵ ΔG0 = − 2.303 RTlog10 KP
∴ ΔG0 = − 2.303 × 8.314 × 10−3 × 298 × log10 (3.358 × 1017)
= − 2.303 × 8.314 × 10−3 × 298 × 17.526
ΔG0 = − 100 kJ mol−1
The value of ΔG0 is negative, i.e. decreasing.
Hence the reaction is spontaneous.
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Spontaneous (Irreversible) Process
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