Question

Calculate the kinetic energy of 10 gram of Argon molecules at 127°C.
[Universal gas constant R = 8320 J/k mole K. Atomic weight of Argon = 40]

Answer 1

Given:

R = 8320 J/k mole K

M₀ = 40

T = 127°C = 127 + 273 = 400K

To find:

K.E for 10g = ?

Formula:

`K.E=(3RT)/(2M_o)xxM`

Solution:

`K.E=(3RT)/(2M_o)xxM`

`K.E=(3xx8320xx400xx0.01)/(2xx40)`

K.E = 1248J

The kinetic energy of 10 grams of Argon molecules at 127°C is 1248J of Argon.