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Question
Calculate magnetic moment of a divalent cation of an element for which atomic number is 24.
Short Note
Solution
Electronic configuration of 22M2+ ion is [Ar] 3d4.
Number of unpaired electrons = 4
μ = `sqrt(n(n + 2))` where n = 4
∴ μ = `sqrt(4 xx 6) = sqrt24 = 4.90 "B.M"`
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