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Question
Calculate ΔS of the surrounding if the standard enthalpy of formation of methanol is − 238.9 kJ mol−1.
Numerical
Solution
Given: ΔfH0 = − 238.9 kJ mol−1
Standard mean temperature,
T = 25°C = 25 + 273 = 298 K
Now, Δsurr.S = `(Delta_fH^0)/T`
= `(- 238.9)/298`
= 0.8017 kJK−1
∴ Δsurr.S = 801.7 JK−1
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Enthalpy (H)
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