Question

Calculate the amount of heat liberated during formation of 2. 7 kg of water if heat of formation of water is - 284.5 kJ mol^-1.

Options

• 4.267 × 10⁴ kJ

• 4.267 × 10³ kJ

• 1.896 × 10⁴ kJ

• 2.896 × 10³ kJ

Answer 1

4.267 × 10⁴ kJ

Explanation:

Since, 18 × 10^-3 kg of H₂O ≡ - 284.5 kJ

                    2.7 kg of H₂O = - 284.5 × 2.7                                                           18 × 10^-3 

= 42.675 × 10^-3 = 4.2675 × 10⁴ kJ