Advertisements
Advertisements
Question
Calculate the amount of work done during isothermal expansion of a gas from a volume of 4 dm3 to 6 dm3 against a constant external pressure of 3 atmosphere?
Options
- 607.8
-60.8 J
- 30.4 J
- 6.0 J
MCQ
Solution
- 607.8
Explanation:
V1 = 4 dm3, V2 = 6 dm3, Pex = 3 atm
Now, W = - Pex (V2 - V1) = - 3(6 - 4)
= - 6 L atm = - 6 × 101.3 J
W = - 607.8 J
shaalaa.com
First Law of Thermodynamics
Is there an error in this question or solution?