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Question
Calculate the difference between heat of combustion of carbon monoxide gas at constant pressure and at constant volume at 27°C? (R = 2 cal K-1 mol-1).
Options
54 cal
- 600 cal
- 300 cal
27 cal
MCQ
Solution
- 300 cal
Explanation:
Given,
T = 27°C = 300 K
R = 2 cal K-1 mol-1
Reaction for combustion of carbon monoxide is given as:
\[\ce{CO(g) + 1/2 O2(g) -> CO2(g)}\]
∴ Δng = 1 - 1.5 = - `1/2`
Now, the difference between heat of combustion of carbon monoxide gas at constant pressure and at constant volume is given by
ΔH - ΔU = Δng RT
∴ ΔH - ΔU = `- 1/2 xx 2 xx 300` = - 300 cal
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