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Question
Calculate the mass percentage of benzene (C6H6) and carbon tetrachloride (CCl4) if 22 g of benzene is dissolved in 122 g of carbon tetrachloride.
Solution
Mass of solution = Mass of benzene + Mass of carbon tetrachloride
= 22 g + 122 g
= 144 g
Mass percentage of benzene = `"Mass of benzene"/"Mass of solution" xx 100`
= `(22 "g")/(144 "g") xx 100`
= 15.28%
Mass percentage of carbon tetrachloride = `"Mass of carbon tetrachloride"/"Mass of solution" xx 100`
= `(122 "g")/(144 "g") xx 100`
= 84.72%
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